how-long-the-list-is

The number the comparison was missing

What it costs to choose the tuning parameter for every candidate separately rather than once for the table, under AR(1) at 0.8, paired on the draw. The window's figure is the one the earlier field reported; the order's is the one it named and did not make. They are the same size — 0.00401 against 0.00360, at 2.30 and 1.72 paired standard errors — and matching the lists at eight values leaves them the same size again. The prediction that the longer list would make the order's cost the larger of the two is not what happens; what happens is that the two rules cost the same once they are scored by the same criterion, which took a missing term to arrange.

How long the list iswide4 views

What else it draws

The same object, drawn to answer the other questions the essays put to it.

The extra error from choosing a tuning parameter per candidate, under AR(1) at 0.8, three ways. Scored by the criterion this collection has used for a sieve since the estimated-covariance field — which carries no determinant — a per-candidate order costs -0.00011, at -0.16 standard errors, and the honest reading of that is nothing. Scored by the criterion the window's rule has always used, which carries the volume its whitening moves, the same rule costs 0.00415 at 2.02 — the window's own 0.00401. The rules were never different. The criteria were.

Each cell is a tuning list of exactly two sieve orders, the row's and the column's, and its shade is how often fifteen candidate regressions choose different values from it, at a true null over 240 draws. Every pair holding order zero disagrees on no draw at all, because the criterion never picks zero under this law. Every adjacent pair of positive orders disagrees on between 17% and 25% of draws — 22.1% for one and two, 25.0% for eleven and twelve — and the rate falls as the two orders move apart, to 5.0% for one and twelve. The largest cell is 25.0%.

Every two-value list of autoregressive orders from one to twelve, read on the same 2400 draws of a first-order autoregression at a hundred and twenty rows: each cell is the average regret of choosing the order per candidate rather than once for the table, on the draws where the fifteen candidates disagree about it. The cost grows away from the diagonal and stays level along it. Next to the diagonal, a quarrel between neighbouring orders costs 0.00126 for one and two and 0.00088 for eleven and twelve; four orders apart it costs 0.00803 and 0.00802; eleven apart, 0.02436. Every list holding order zero is left off because the candidates never disagree about one.

Where it is used

5 essays draw this figure, each at the numbers its own argument is about, so the same picture answers 5 different questions.

All 80 figures

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